2x^2-3x+1(x+5)=

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Solution for 2x^2-3x+1(x+5)= equation:


Simplifying
2x2 + -3x + 1(x + 5) = 0

Reorder the terms:
2x2 + -3x + 1(5 + x) = 0
2x2 + -3x + (5 * 1 + x * 1) = 0
2x2 + -3x + (5 + 1x) = 0

Reorder the terms:
5 + -3x + 1x + 2x2 = 0

Combine like terms: -3x + 1x = -2x
5 + -2x + 2x2 = 0

Solving
5 + -2x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
2.5 + -1x + x2 = 0

Move the constant term to the right:

Add '-2.5' to each side of the equation.
2.5 + -1x + -2.5 + x2 = 0 + -2.5

Reorder the terms:
2.5 + -2.5 + -1x + x2 = 0 + -2.5

Combine like terms: 2.5 + -2.5 = 0.0
0.0 + -1x + x2 = 0 + -2.5
-1x + x2 = 0 + -2.5

Combine like terms: 0 + -2.5 = -2.5
-1x + x2 = -2.5

The x term is -1x.  Take half its coefficient (-0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1x + 0.25 + x2 = -2.5 + 0.25

Reorder the terms:
0.25 + -1x + x2 = -2.5 + 0.25

Combine like terms: -2.5 + 0.25 = -2.25
0.25 + -1x + x2 = -2.25

Factor a perfect square on the left side:
(x + -0.5)(x + -0.5) = -2.25

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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